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3(1/9x-2)=9
We move all terms to the left:
3(1/9x-2)-(9)=0
Domain of the equation: 9x-2)!=0We multiply parentheses
x∈R
3x-6-9=0
We add all the numbers together, and all the variables
3x-15=0
We move all terms containing x to the left, all other terms to the right
3x=15
x=15/3
x=5
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