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3(1-x)+5(1-x)=3(x-1)+1
We move all terms to the left:
3(1-x)+5(1-x)-(3(x-1)+1)=0
We add all the numbers together, and all the variables
3(-1x+1)+5(-1x+1)-(3(x-1)+1)=0
We multiply parentheses
-3x-5x-(3(x-1)+1)+3+5=0
We calculate terms in parentheses: -(3(x-1)+1), so:We add all the numbers together, and all the variables
3(x-1)+1
We multiply parentheses
3x-3+1
We add all the numbers together, and all the variables
3x-2
Back to the equation:
-(3x-2)
-8x-(3x-2)+8=0
We get rid of parentheses
-8x-3x+2+8=0
We add all the numbers together, and all the variables
-11x+10=0
We move all terms containing x to the left, all other terms to the right
-11x=-10
x=-10/-11
x=10/11
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