3(1-x)+10=9(x-2)+7

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Solution for 3(1-x)+10=9(x-2)+7 equation: 



3(1-x)+10=9(x-2)+7

We move all terms to the left:

3(1-x)+10-(9(x-2)+7)=0

We add all the numbers together, and all the variables

3(-1x+1)-(9(x-2)+7)+10=0

We multiply parentheses

-3x-(9(x-2)+7)+3+10=0



We calculate terms in parentheses: -(9(x-2)+7), so:

9(x-2)+7

We multiply parentheses

9x-18+7

We add all the numbers together, and all the variables

9x-11

Back to the equation:

-(9x-11)



We add all the numbers together, and all the variables

-3x-(9x-11)+13=0

We get rid of parentheses

-3x-9x+11+13=0

We add all the numbers together, and all the variables

-12x+24=0

We move all terms containing x to the left, all other terms to the right

-12x=-24

x=-24/-12

x=+2

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