3(1-3x)=3(3x+4)

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Solution for 3(1-3x)=3(3x+4) equation: 



3(1-3x)=3(3x+4)

We move all terms to the left:

3(1-3x)-(3(3x+4))=0

We add all the numbers together, and all the variables

3(-3x+1)-(3(3x+4))=0

We multiply parentheses

-9x-(3(3x+4))+3=0



We calculate terms in parentheses: -(3(3x+4)), so:

3(3x+4)

We multiply parentheses

9x+12

Back to the equation:

-(9x+12)



We get rid of parentheses

-9x-9x-12+3=0

We add all the numbers together, and all the variables

-18x-9=0

We move all terms containing x to the left, all other terms to the right

-18x=9

x=9/-18

x=-1/2

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