3(1-3x)=2(-4x+5)

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Solution for 3(1-3x)=2(-4x+5) equation: 



3(1-3x)=2(-4x+5)

We move all terms to the left:

3(1-3x)-(2(-4x+5))=0

We add all the numbers together, and all the variables

3(-3x+1)-(2(-4x+5))=0

We multiply parentheses

-9x-(2(-4x+5))+3=0



We calculate terms in parentheses: -(2(-4x+5)), so:

2(-4x+5)

We multiply parentheses

-8x+10

Back to the equation:

-(-8x+10)



We get rid of parentheses

-9x+8x-10+3=0

We add all the numbers together, and all the variables

-1x-7=0

We move all terms containing x to the left, all other terms to the right

-x=7

x=7/-1

x=-7

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