3(1-3d)=2(7d+6)

Solution for 3(1-3d)=2(7d+6) equation:

3(1-3d)=2(7d+6)

We move all terms to the left:

3(1-3d)-(2(7d+6))=0

We add all the numbers together, and all the variables

3(-3d+1)-(2(7d+6))=0

We multiply parentheses

-9d-(2(7d+6))+3=0


We calculate terms in parentheses: -(2(7d+6)), so:

2(7d+6)

We multiply parentheses

14d+12

Back to the equation:

-(14d+12)


We get rid of parentheses

-9d-14d-12+3=0

We add all the numbers together, and all the variables

-23d-9=0

We move all terms containing d to the left, all other terms to the right

-23d=9

d=9/-23

d=-9/23