3(1-12c)=-11(1-3c)+7c

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Solution for 3(1-12c)=-11(1-3c)+7c equation: 



3(1-12c)=-11(1-3c)+7c

We move all terms to the left:

3(1-12c)-(-11(1-3c)+7c)=0

We add all the numbers together, and all the variables

3(-12c+1)-(-11(-3c+1)+7c)=0

We multiply parentheses

-36c-(-11(-3c+1)+7c)+3=0



We calculate terms in parentheses: -(-11(-3c+1)+7c), so:

-11(-3c+1)+7c

We add all the numbers together, and all the variables

7c-11(-3c+1)

We multiply parentheses

7c+33c-11

We add all the numbers together, and all the variables

40c-11

Back to the equation:

-(40c-11)



We get rid of parentheses

-36c-40c+11+3=0

We add all the numbers together, and all the variables

-76c+14=0

We move all terms containing c to the left, all other terms to the right

-76c=-14

c=-14/-76

c=7/38

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