3(1+6c)=4c-67

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Solution for 3(1+6c)=4c-67 equation: 



3(1+6c)=4c-67

We move all terms to the left:

3(1+6c)-(4c-67)=0

We add all the numbers together, and all the variables

3(6c+1)-(4c-67)=0

We multiply parentheses

18c-(4c-67)+3=0

We get rid of parentheses

18c-4c+67+3=0

We add all the numbers together, and all the variables

14c+70=0

We move all terms containing c to the left, all other terms to the right

14c=-70

c=-70/14

c=-5

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