3(1+4r)+7r=3(1-8r)

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Solution for 3(1+4r)+7r=3(1-8r) equation: 



3(1+4r)+7r=3(1-8r)

We move all terms to the left:

3(1+4r)+7r-(3(1-8r))=0

We add all the numbers together, and all the variables

3(4r+1)+7r-(3(-8r+1))=0

We add all the numbers together, and all the variables

7r+3(4r+1)-(3(-8r+1))=0

We multiply parentheses

7r+12r-(3(-8r+1))+3=0



We calculate terms in parentheses: -(3(-8r+1)), so:

3(-8r+1)

We multiply parentheses

-24r+3

Back to the equation:

-(-24r+3)



We add all the numbers together, and all the variables

19r-(-24r+3)+3=0

We get rid of parentheses

19r+24r-3+3=0

We add all the numbers together, and all the variables

43r=0

r=0/43

r=0

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