3(1+2r)=-5(6+r)

Solution for 3(1+2r)=-5(6+r) equation:

3(1+2r)=-5(6+r)

We move all terms to the left:

3(1+2r)-(-5(6+r))=0

We add all the numbers together, and all the variables

3(2r+1)-(-5(r+6))=0

We multiply parentheses

6r-(-5(r+6))+3=0


We calculate terms in parentheses: -(-5(r+6)), so:

-5(r+6)

We multiply parentheses

-5r-30

Back to the equation:

-(-5r-30)


We get rid of parentheses

6r+5r+30+3=0

We add all the numbers together, and all the variables

11r+33=0

We move all terms containing r to the left, all other terms to the right

11r=-33

r=-33/11

r=-3