3(-y-5)+4=2(y+13)+3

Solution for 3(-y-5)+4=2(y+13)+3 equation:

3(-y-5)+4=2(y+13)+3

We move all terms to the left:

3(-y-5)+4-(2(y+13)+3)=0

We add all the numbers together, and all the variables

3(-1y-5)-(2(y+13)+3)+4=0

We multiply parentheses

-3y-(2(y+13)+3)-15+4=0


We calculate terms in parentheses: -(2(y+13)+3), so:

2(y+13)+3

We multiply parentheses

2y+26+3

We add all the numbers together, and all the variables

2y+29

Back to the equation:

-(2y+29)


We add all the numbers together, and all the variables

-3y-(2y+29)-11=0

We get rid of parentheses

-3y-2y-29-11=0

We add all the numbers together, and all the variables

-5y-40=0

We move all terms containing y to the left, all other terms to the right

-5y=40

y=40/-5

y=-8