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3(-r+4)=7(2+r)-6
We move all terms to the left:
3(-r+4)-(7(2+r)-6)=0
We add all the numbers together, and all the variables
3(-1r+4)-(7(r+2)-6)=0
We multiply parentheses
-3r-(7(r+2)-6)+12=0
We calculate terms in parentheses: -(7(r+2)-6), so:We get rid of parentheses
7(r+2)-6
We multiply parentheses
7r+14-6
We add all the numbers together, and all the variables
7r+8
Back to the equation:
-(7r+8)
-3r-7r-8+12=0
We add all the numbers together, and all the variables
-10r+4=0
We move all terms containing r to the left, all other terms to the right
-10r=-4
r=-4/-10
r=2/5
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