3(-f-10)=10+f

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Solution for 3(-f-10)=10+f equation: 



3(-f-10)=10+f

We move all terms to the left:

3(-f-10)-(10+f)=0

We add all the numbers together, and all the variables

3(-1f-10)-(f+10)=0

We multiply parentheses

-3f-(f+10)-30=0

We get rid of parentheses

-3f-f-10-30=0

We add all the numbers together, and all the variables

-4f-40=0

We move all terms containing f to the left, all other terms to the right

-4f=40

f=40/-4

f=-10

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