3(-c+3)=5(c+6)+11=

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Solution for 3(-c+3)=5(c+6)+11= equation: 



3(-c+3)=5(c+6)+11=

We move all terms to the left:

3(-c+3)-(5(c+6)+11)=0

We add all the numbers together, and all the variables

3(-1c+3)-(5(c+6)+11)=0

We multiply parentheses

-3c-(5(c+6)+11)+9=0



We calculate terms in parentheses: -(5(c+6)+11), so:

5(c+6)+11

We multiply parentheses

5c+30+11

We add all the numbers together, and all the variables

5c+41

Back to the equation:

-(5c+41)



We get rid of parentheses

-3c-5c-41+9=0

We add all the numbers together, and all the variables

-8c-32=0

We move all terms containing c to the left, all other terms to the right

-8c=32

c=32/-8

c=-4

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