3(-99+3x)=7(33+x)

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Solution for 3(-99+3x)=7(33+x) equation: 



3(-99+3x)=7(33+x)

We move all terms to the left:

3(-99+3x)-(7(33+x))=0

We add all the numbers together, and all the variables

3(3x-99)-(7(x+33))=0

We multiply parentheses

9x-(7(x+33))-297=0



We calculate terms in parentheses: -(7(x+33)), so:

7(x+33)

We multiply parentheses

7x+231

Back to the equation:

-(7x+231)



We get rid of parentheses

9x-7x-231-297=0

We add all the numbers together, and all the variables

2x-528=0

We move all terms containing x to the left, all other terms to the right

2x=528

x=528/2

x=264

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