3(-8+6x)=32+4x

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Solution for 3(-8+6x)=32+4x equation: 



3(-8+6x)=32+4x

We move all terms to the left:

3(-8+6x)-(32+4x)=0

We add all the numbers together, and all the variables

3(6x-8)-(4x+32)=0

We multiply parentheses

18x-(4x+32)-24=0

We get rid of parentheses

18x-4x-32-24=0

We add all the numbers together, and all the variables

14x-56=0

We move all terms containing x to the left, all other terms to the right

14x=56

x=56/14

x=4

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