3(-4y+-4)=12

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Solution for 3(-4y+-4)=12 equation: 



3(-4y+-4)=12

We move all terms to the left:

3(-4y+-4)-(12)=0

We add all the numbers together, and all the variables

3(-4y-4)-12=0

We multiply parentheses

-12y-12-12=0

We add all the numbers together, and all the variables

-12y-24=0

We move all terms containing y to the left, all other terms to the right

-12y=24

y=24/-12

y=-2

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