3(-4/3b+1/3c)+4b=c

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Solution for 3(-4/3b+1/3c)+4b=c equation: 


x in (-oo:+oo)

3*((-4/3)*b+(1/3)*c)+4*b = c // - c

3*((-4/3)*b+(1/3)*c)+4*b-c = 0

3*(1/3*c-4/3*b)+4*b-c = 0

3*(1/3*c-4/3*b)+4*b-c = 0

c-c = 0

0 = 0

0 = 0

x belongs to the empty set

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