3(-3+m)=10(m-2)

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Solution for 3(-3+m)=10(m-2) equation: 



3(-3+m)=10(m-2)

We move all terms to the left:

3(-3+m)-(10(m-2))=0

We add all the numbers together, and all the variables

3(m-3)-(10(m-2))=0

We multiply parentheses

3m-(10(m-2))-9=0



We calculate terms in parentheses: -(10(m-2)), so:

10(m-2)

We multiply parentheses

10m-20

Back to the equation:

-(10m-20)



We get rid of parentheses

3m-10m+20-9=0

We add all the numbers together, and all the variables

-7m+11=0

We move all terms containing m to the left, all other terms to the right

-7m=-11

m=-11/-7

m=1+4/7

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