3(-2x-6)=6(x+2)+6

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Solution for 3(-2x-6)=6(x+2)+6 equation: 



3(-2x-6)=6(x+2)+6

We move all terms to the left:

3(-2x-6)-(6(x+2)+6)=0

We multiply parentheses

-6x-(6(x+2)+6)-18=0



We calculate terms in parentheses: -(6(x+2)+6), so:

6(x+2)+6

We multiply parentheses

6x+12+6

We add all the numbers together, and all the variables

6x+18

Back to the equation:

-(6x+18)



We get rid of parentheses

-6x-6x-18-18=0

We add all the numbers together, and all the variables

-12x-36=0

We move all terms containing x to the left, all other terms to the right

-12x=36

x=36/-12

x=-3

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