3(-2x-3)=4(x+4)-12

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Solution for 3(-2x-3)=4(x+4)-12 equation: 



3(-2x-3)=4(x+4)-12

We move all terms to the left:

3(-2x-3)-(4(x+4)-12)=0

We multiply parentheses

-6x-(4(x+4)-12)-9=0



We calculate terms in parentheses: -(4(x+4)-12), so:

4(x+4)-12

We multiply parentheses

4x+16-12

We add all the numbers together, and all the variables

4x+4

Back to the equation:

-(4x+4)



We get rid of parentheses

-6x-4x-4-9=0

We add all the numbers together, and all the variables

-10x-13=0

We move all terms containing x to the left, all other terms to the right

-10x=13

x=13/-10

x=-1+3/10

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