3(-2x+5)=(-8x+10)/2

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Solution for 3(-2x+5)=(-8x+10)/2 equation: 



3(-2x+5)=(-8x+10)/2

We move all terms to the left:

3(-2x+5)-((-8x+10)/2)=0

We multiply parentheses

-6x-((-8x+10)/2)+15=0

We multiply all the terms by the denominator


-6x*2)-((-8x+10)+15*2)=0

We add all the numbers together, and all the variables

-6x*2)-((-8x+10)=0

Wy multiply elements

-12x^2=0

a = -12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-12)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-24}=0$

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