3(-2r-4)+r=18

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Solution for 3(-2r-4)+r=18 equation: 



3(-2r-4)+r=18

We move all terms to the left:

3(-2r-4)+r-(18)=0

We add all the numbers together, and all the variables

r+3(-2r-4)-18=0

We multiply parentheses

r-6r-12-18=0

We add all the numbers together, and all the variables

-5r-30=0

We move all terms containing r to the left, all other terms to the right

-5r=30

r=30/-5

r=-6

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