3(-2j-6)=-6j-18

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Solution for 3(-2j-6)=-6j-18 equation: 



3(-2j-6)=-6j-18

We move all terms to the left:

3(-2j-6)-(-6j-18)=0

We multiply parentheses

-6j-(-6j-18)-18=0

We get rid of parentheses

-6j+6j+18-18=0

We add all the numbers together, and all the variables

=0

j=0/1

j=0

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