3(-20-2x)=11x-138-4x

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Solution for 3(-20-2x)=11x-138-4x equation:



3(-20-2x)=11x-138-4x
We move all terms to the left:
3(-20-2x)-(11x-138-4x)=0
We add all the numbers together, and all the variables
3(-2x-20)-(7x-138)=0
We multiply parentheses
-6x-(7x-138)-60=0
We get rid of parentheses
-6x-7x+138-60=0
We add all the numbers together, and all the variables
-13x+78=0
We move all terms containing x to the left, all other terms to the right
-13x=-78
x=-78/-13
x=+6

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