3(-2-3z)=9z-4

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Solution for 3(-2-3z)=9z-4 equation: 



3(-2-3z)=9z-4

We move all terms to the left:

3(-2-3z)-(9z-4)=0

We add all the numbers together, and all the variables

3(-3z-2)-(9z-4)=0

We multiply parentheses

-9z-(9z-4)-6=0

We get rid of parentheses

-9z-9z+4-6=0

We add all the numbers together, and all the variables

-18z-2=0

We move all terms containing z to the left, all other terms to the right

-18z=2

z=2/-18

z=-1/9

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