3(-2+4k)=5(2k-4)

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Solution for 3(-2+4k)=5(2k-4) equation: 



3(-2+4k)=5(2k-4)

We move all terms to the left:

3(-2+4k)-(5(2k-4))=0

We add all the numbers together, and all the variables

3(4k-2)-(5(2k-4))=0

We multiply parentheses

12k-(5(2k-4))-6=0



We calculate terms in parentheses: -(5(2k-4)), so:

5(2k-4)

We multiply parentheses

10k-20

Back to the equation:

-(10k-20)



We get rid of parentheses

12k-10k+20-6=0

We add all the numbers together, and all the variables

2k+14=0

We move all terms containing k to the left, all other terms to the right

2k=-14

k=-14/2

k=-7

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