3(-10c-6)=-12c-18-18c

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Solution for 3(-10c-6)=-12c-18-18c equation: 



3(-10c-6)=-12c-18-18c

We move all terms to the left:

3(-10c-6)-(-12c-18-18c)=0

We add all the numbers together, and all the variables

3(-10c-6)-(-30c-18)=0

We multiply parentheses

-30c-(-30c-18)-18=0

We get rid of parentheses

-30c+30c+18-18=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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