3((1/3)a+3)=27

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Solution for 3((1/3)a+3)=27 equation:



3((1/3)a+3)=27
We move all terms to the left:
3((1/3)a+3)-(27)=0
Domain of the equation: 3)a+3)!=0
a!=0/1
a!=0
a∈R
We add all the numbers together, and all the variables
3((+1/3)a+3)-27=0
We multiply all the terms by the denominator
3((+1-27*3)a+3)=0
We add all the numbers together, and all the variables
3((-80)a+3)=0

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