3^2x+3-2.9^x+1=1/9

Solution for 3^2x+3-2.9^x+1=1/9 equation:

3^2x+3-2.9^x+1=1/9

We move all terms to the left:

3^2x+3-2.9^x+1-(1/9)=0

We add all the numbers together, and all the variables

3^2x-2.9^x+3+1-(+1/9)=0

We add all the numbers together, and all the variables

3^2x-2.9^x+4-(+1/9)=0

We get rid of parentheses

3^2x-2.9^x+4-1/9=0

We multiply all the terms by the denominator


3^2x*9-(2.9^x)*9-1+4*9=0

We add all the numbers together, and all the variables

3^2x*9-(2.9^x)*9+35=0

We multiply parentheses

3^2x*9-18x+35=0

Wy multiply elements

27x^2-18x+35=0

a = 27; b = -18; c = +35;
Δ = b2-4ac
Δ = -182-4·27·35
Δ = -3456
Delta is less than zero, so there is no solution for the equation