2z/3=(z-3)/2

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Solution for 2z/3=(z-3)/2 equation:



2z/3=(z-3)/2
We move all terms to the left:
2z/3-((z-3)/2)=0
We calculate fractions
4z^2/()+(-((z-3)*3)/()=0
We calculate terms in parentheses: +(-((z-3)*3)/(), so:
-((z-3)*3)/(
We multiply all the terms by the denominator
-((z-3)*3)
We calculate terms in parentheses: -((z-3)*3), so:
(z-3)*3
We multiply parentheses
3z-9
Back to the equation:
-(3z-9)
We get rid of parentheses
-3z+9
Back to the equation:
+(-3z+9)
We get rid of parentheses
4z^2/()-3z+9=0
We multiply all the terms by the denominator
4z^2-3z*()+9*()=0
We add all the numbers together, and all the variables
4z^2-3z*()=0

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