2z/2-17/3=2z/3-3/2

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Solution for 2z/2-17/3=2z/3-3/2 equation: 


z in (-oo:+oo)

(2*z)/2-(17/3) = (2*z)/3-(3/2) // - (2*z)/3-(3/2)

(2*z)/2-((2*z)/3)-(17/3)+3/2 = 0

(2*z)/2+(-2/3)*z-17/3+3/2 = 0

1/3*z-25/6 = 0 // + 25/6

1/3*z = 25/6 // : 1/3

z = 25/6/1/3

z = 25/2

z = 25/2

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