2z-6=2(z+2)+10

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Solution for 2z-6=2(z+2)+10 equation: 



2z-6=2(z+2)+10

We move all terms to the left:

2z-6-(2(z+2)+10)=0



We calculate terms in parentheses: -(2(z+2)+10), so:

2(z+2)+10

We multiply parentheses

2z+4+10

We add all the numbers together, and all the variables

2z+14

Back to the equation:

-(2z+14)



We get rid of parentheses

2z-2z-14-6=0

We add all the numbers together, and all the variables

-20!=0

There is no solution for this equation

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