2z-4z-20=5(z+10)

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Solution for 2z-4z-20=5(z+10) equation: 



2z-4z-20=5(z+10)

We move all terms to the left:

2z-4z-20-(5(z+10))=0

We add all the numbers together, and all the variables

-2z-(5(z+10))-20=0



We calculate terms in parentheses: -(5(z+10)), so:

5(z+10)

We multiply parentheses

5z+50

Back to the equation:

-(5z+50)



We get rid of parentheses

-2z-5z-50-20=0

We add all the numbers together, and all the variables

-7z-70=0

We move all terms containing z to the left, all other terms to the right

-7z=70

z=70/-7

z=-10

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