2z-4(z+1)=-(5z+2)+z

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Solution for 2z-4(z+1)=-(5z+2)+z equation:


Simplifying
2z + -4(z + 1) = -1(5z + 2) + z

Reorder the terms:
2z + -4(1 + z) = -1(5z + 2) + z
2z + (1 * -4 + z * -4) = -1(5z + 2) + z
2z + (-4 + -4z) = -1(5z + 2) + z

Reorder the terms:
-4 + 2z + -4z = -1(5z + 2) + z

Combine like terms: 2z + -4z = -2z
-4 + -2z = -1(5z + 2) + z

Reorder the terms:
-4 + -2z = -1(2 + 5z) + z
-4 + -2z = (2 * -1 + 5z * -1) + z
-4 + -2z = (-2 + -5z) + z

Combine like terms: -5z + z = -4z
-4 + -2z = -2 + -4z

Solving
-4 + -2z = -2 + -4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '4z' to each side of the equation.
-4 + -2z + 4z = -2 + -4z + 4z

Combine like terms: -2z + 4z = 2z
-4 + 2z = -2 + -4z + 4z

Combine like terms: -4z + 4z = 0
-4 + 2z = -2 + 0
-4 + 2z = -2

Add '4' to each side of the equation.
-4 + 4 + 2z = -2 + 4

Combine like terms: -4 + 4 = 0
0 + 2z = -2 + 4
2z = -2 + 4

Combine like terms: -2 + 4 = 2
2z = 2

Divide each side by '2'.
z = 1

Simplifying
z = 1

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