2z-33=3(z+4)-4z

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Solution for 2z-33=3(z+4)-4z equation: 



2z-33=3(z+4)-4z

We move all terms to the left:

2z-33-(3(z+4)-4z)=0



We calculate terms in parentheses: -(3(z+4)-4z), so:

3(z+4)-4z

We add all the numbers together, and all the variables

-4z+3(z+4)

We multiply parentheses

-4z+3z+12

We add all the numbers together, and all the variables

-1z+12

Back to the equation:

-(-1z+12)



We get rid of parentheses

2z+1z-12-33=0

We add all the numbers together, and all the variables

3z-45=0

We move all terms containing z to the left, all other terms to the right

3z=45

z=45/3

z=15

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