2z-3(z+1)=(6z+3)+z

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Solution for 2z-3(z+1)=(6z+3)+z equation:


Simplifying
2z + -3(z + 1) = (6z + 3) + z

Reorder the terms:
2z + -3(1 + z) = (6z + 3) + z
2z + (1 * -3 + z * -3) = (6z + 3) + z
2z + (-3 + -3z) = (6z + 3) + z

Reorder the terms:
-3 + 2z + -3z = (6z + 3) + z

Combine like terms: 2z + -3z = -1z
-3 + -1z = (6z + 3) + z

Reorder the terms:
-3 + -1z = (3 + 6z) + z

Remove parenthesis around (3 + 6z)
-3 + -1z = 3 + 6z + z

Combine like terms: 6z + z = 7z
-3 + -1z = 3 + 7z

Solving
-3 + -1z = 3 + 7z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-7z' to each side of the equation.
-3 + -1z + -7z = 3 + 7z + -7z

Combine like terms: -1z + -7z = -8z
-3 + -8z = 3 + 7z + -7z

Combine like terms: 7z + -7z = 0
-3 + -8z = 3 + 0
-3 + -8z = 3

Add '3' to each side of the equation.
-3 + 3 + -8z = 3 + 3

Combine like terms: -3 + 3 = 0
0 + -8z = 3 + 3
-8z = 3 + 3

Combine like terms: 3 + 3 = 6
-8z = 6

Divide each side by '-8'.
z = -0.75

Simplifying
z = -0.75

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