2z-1/5=1/2(3z+1)

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Solution for 2z-1/5=1/2(3z+1) equation: 



2z-1/5=1/2(3z+1)

We move all terms to the left:

2z-1/5-(1/2(3z+1))=0



Domain of the equation: 2(3z+1))!=0

z∈R



We calculate fractions


2z+()/30z+(-2z3/30z=0

We multiply all the terms by the denominator


2z*30z+(-2z3+()=0



We calculate terms in parentheses: +(-2z3+(), so:

-2z3+(

We add all the numbers together, and all the variables

-2z^3

We do not support ezpression: z^3

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