2z+2z+((2+1/2)+2z)=17

Solution for 2z+2z+((2+1/2)+2z)=17 equation:

2z+2z+((2+1/2)+2z)=17

We move all terms to the left:

2z+2z+((2+1/2)+2z)-(17)=0


Domain of the equation: 2)+2z)!=0

z!=0/1

z!=0

z∈R


We add all the numbers together, and all the variables

2z+2z+((1/2+2)+2z)-17=0

We add all the numbers together, and all the variables

4z+((1/2+2)+2z)-17=0

We multiply all the terms by the denominator


4z*2+2)+2z)+((1+2)+2z)-17*2=0

We add all the numbers together, and all the variables

4z*2+2)+2z)+(3+2z)-17*2=0

Wy multiply elements

8z+2)+2z)+(3+2z)-17*2=0

We add all the numbers together, and all the variables

8z+2)+2z)+(2z+3)-17*2=0