2z+1=3(z+1)

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Solution for 2z+1=3(z+1) equation: 



2z+1=3(z+1)

We move all terms to the left:

2z+1-(3(z+1))=0



We calculate terms in parentheses: -(3(z+1)), so:

3(z+1)

We multiply parentheses

3z+3

Back to the equation:

-(3z+3)



We get rid of parentheses

2z-3z-3+1=0

We add all the numbers together, and all the variables

-1z-2=0

We move all terms containing z to the left, all other terms to the right

-z=2

z=2/-1

z=-2

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