2z+13=10+4z+5(3-z)

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Solution for 2z+13=10+4z+5(3-z) equation: 



2z+13=10+4z+5(3-z)

We move all terms to the left:

2z+13-(10+4z+5(3-z))=0

We add all the numbers together, and all the variables

2z-(10+4z+5(-1z+3))+13=0



We calculate terms in parentheses: -(10+4z+5(-1z+3)), so:

10+4z+5(-1z+3)

determiningTheFunctionDomain
4z+5(-1z+3)+10

We multiply parentheses

4z-5z+15+10

We add all the numbers together, and all the variables

-1z+25

Back to the equation:

-(-1z+25)



We get rid of parentheses

2z+1z-25+13=0

We add all the numbers together, and all the variables

3z-12=0

We move all terms containing z to the left, all other terms to the right

3z=12

z=12/3

z=4

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