2y=(5y-3)=6

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Solution for 2y=(5y-3)=6 equation: 



2y=(5y-3)=6

We move all terms to the left:

2y-((5y-3))=0



We calculate terms in parentheses: -((5y-3)), so:

(5y-3)

We get rid of parentheses

5y-3

Back to the equation:

-(5y-3)



We get rid of parentheses

2y-5y+3=0

We add all the numbers together, and all the variables

-3y+3=0

We move all terms containing y to the left, all other terms to the right

-3y=-3

y=-3/-3

y=1

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