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2y-8=-1/5(3-5y)
We move all terms to the left:
2y-8-(-1/5(3-5y))=0
Domain of the equation: 5(3-5y))!=0We add all the numbers together, and all the variables
y∈R
2y-(-1/5(-5y+3))-8=0
We multiply all the terms by the denominator
2y*5(-5y+3))-(-8*5(-5y+3))-1=0
Wy multiply elements
10y^2(--40y(-=0
We use the square of the difference formula
10y^2(+40y(-=0
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