2y-8+2(3y+1)=-2(y+5)

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Solution for 2y-8+2(3y+1)=-2(y+5) equation: 



2y-8+2(3y+1)=-2(y+5)

We move all terms to the left:

2y-8+2(3y+1)-(-2(y+5))=0

We multiply parentheses

2y+6y-(-2(y+5))+2-8=0



We calculate terms in parentheses: -(-2(y+5)), so:

-2(y+5)

We multiply parentheses

-2y-10

Back to the equation:

-(-2y-10)



We add all the numbers together, and all the variables

8y-(-2y-10)-6=0

We get rid of parentheses

8y+2y+10-6=0

We add all the numbers together, and all the variables

10y+4=0

We move all terms containing y to the left, all other terms to the right

10y=-4

y=-4/10

y=-2/5

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