2y-6=2((3y+1)/4)

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Solution for 2y-6=2((3y+1)/4) equation: 



2y-6=2((3y+1)/4)

We move all terms to the left:

2y-6-(2((3y+1)/4))=0

We multiply all the terms by the denominator


2y*4))-(2((3y+1)-6*4))=0

We add all the numbers together, and all the variables

2y*4))-(2((3y+1)=0

Wy multiply elements

8y^2=0

a = 8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·8·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{16}=0$

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