2y-5=(4y-3)/2

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Solution for 2y-5=(4y-3)/2 equation: 



2y-5=(4y-3)/2

We move all terms to the left:

2y-5-((4y-3)/2)=0

We multiply all the terms by the denominator


2y*2)-((4y-3)-5*2)=0

We add all the numbers together, and all the variables

2y*2)-((4y-3)=0

Wy multiply elements

4y^2=0

a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{8}=0$

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