2y-5(5y-2)=2-4(-5-y)

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Solution for 2y-5(5y-2)=2-4(-5-y) equation: 



2y-5(5y-2)=2-4(-5-y)

We move all terms to the left:

2y-5(5y-2)-(2-4(-5-y))=0

We add all the numbers together, and all the variables

2y-5(5y-2)-(2-4(-1y-5))=0

We multiply parentheses

2y-25y-(2-4(-1y-5))+10=0



We calculate terms in parentheses: -(2-4(-1y-5)), so:

2-4(-1y-5)

determiningTheFunctionDomain
-4(-1y-5)+2

We multiply parentheses

4y+20+2

We add all the numbers together, and all the variables

4y+22

Back to the equation:

-(4y+22)



We add all the numbers together, and all the variables

-23y-(4y+22)+10=0

We get rid of parentheses

-23y-4y-22+10=0

We add all the numbers together, and all the variables

-27y-12=0

We move all terms containing y to the left, all other terms to the right

-27y=12

y=12/-27

y=-4/9

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