2y-4=3(y+7)

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Solution for 2y-4=3(y+7) equation: 



2y-4=3(y+7)

We move all terms to the left:

2y-4-(3(y+7))=0



We calculate terms in parentheses: -(3(y+7)), so:

3(y+7)

We multiply parentheses

3y+21

Back to the equation:

-(3y+21)



We get rid of parentheses

2y-3y-21-4=0

We add all the numbers together, and all the variables

-1y-25=0

We move all terms containing y to the left, all other terms to the right

-y=25

y=25/-1

y=-25

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