2y-40=4(y-7)

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Solution for 2y-40=4(y-7) equation: 



2y-40=4(y-7)

We move all terms to the left:

2y-40-(4(y-7))=0



We calculate terms in parentheses: -(4(y-7)), so:

4(y-7)

We multiply parentheses

4y-28

Back to the equation:

-(4y-28)



We get rid of parentheses

2y-4y+28-40=0

We add all the numbers together, and all the variables

-2y-12=0

We move all terms containing y to the left, all other terms to the right

-2y=12

y=12/-2

y=-6

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