2y-4+3(y+1)=

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Solution for 2y-4+3(y+1)= equation:


2y-4+3(y+1)=0

We simplify the equation to the form, which is simple to understand 
2y-4+3(y+1)=0

Reorder the terms in parentheses
2y-4+(+3y+3)=0

Remove unnecessary parentheses
+2y-4+3y+3=0

We move all terms containing y to the left and all other terms to the right. 
+2y+3y=0+4-3

We simplify left and right side of the equation. 
+5y=+1

We divide both sides of the equation by 5 to get y. 
y=0.2

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